Category: App Services

All about application services for example, Azure App Service. Angular application, Microsoft .NET Core and EF

Unordered list without bullets

You can remove bullets by setting the list-style-type to none on the CSS for the parent element (typically a <ul>), for example:

ul {
  list-style-type: none;
}

You might also want to add padding: 0 and margin: 0 to that if you want to remove indentation as well.

See Listutorial for a great walkthrough of list formatting techniques.

For more info, continue reading on Stack Overflow

For more info on CSS box model, continue reading on W3 schools

Difference between an array and an object in JavaScript

What’s the difference between “{}” and “[]” while declaring a JavaScript array? Normally I declare like

var a = [];

What is the meaning of declaring the array as var a = {}

Some of the meaning and explanation between [] and {} are;

var a = {}; is an object-key-value pairs. var a = []; is an array-values stored in sequential indexes. We are not creating array when we are using {}, we are creating object

For more info, continue reading on Stack Overflow

Dapper Transaction

Dapper provides different ways to work with transactions. The most common way is to use the BeginTransaction method available on the IDbConnection interface. That will return an instance of IDbTransaction, which you can use with Execute and Query methods to add, remove and modify data in your database tables.

// Open the connection and start a transaction: 
using (var connection = new SqlConnection(connectionString))
{ 
    connection.Open();
	
    using (var tran = connection.BeginTransaction()) 
    { 
        // Execute your queries here
		
        tran.Commit(); //Or rollback 
    }
}

You can also use the TransactionScope class, which provides a much simpler way to deal with transactions:

// Open the connection and start a transaction: 
using (var scope = new TransactionScope()) 
{ 
    // Execute your queries here
	
    scope.Complete(); //Or it will automatically rollback 
}

While using Dapper transaction, i have started getting this error;

"A TransactionScope must be disposed on the same thread that it was created."

Looking around, I figured this out;

In .NET Framework 4.5.1, there is a set of new constructors for TransactionScope that take a TransactionScopeAsyncFlowOption parameter.

According to the MSDN, it enables transaction flow across thread continuations. Here is an example;

using (var tx = new TransactionScope(TransactionScopeAsyncFlowOption.Enabled))
{
    await SomeMethodInTheCallStackAsync()
        .ConfigureAwait(false);

    tx.Complete();
}

For complete detail, read this article.

Reference

https://www.learndapper.com/misc/transaction

ES6: How to access a static getter from an instance

How can i access a static getter from an instance of the class that implements that getter?

for example, i have this class:

class Component {
  static get isComponent() { return true; }

  constructor() {}
}

const c = new Component();

how can i call from “c” “isComponent” of “Component” class? I read around and all I found is something like that:

Object.getPrototypeOf(c).isComponent

but this is not working on my case because there is no “isComponent” method in Component prototype object. The above code works if I write the class like this:

Component.prototype.isComponent = () => { return true; }

but this is not the way i would like to write classes. What am I missing?

statics become properties of the constructor function, which you can access on an instance via the constructor property:

console.log(c.constructor.isComponent);
class Component {
  static get isComponent() { return true; }

  constructor() {}
}

const c = new Component();
console.log(c.constructor.isComponent); // true

Of course, that relies on constructor not having been mucked with. 🙂 Before the class syntax, you’d see people forgetting to set constructor properly in inheritance hierarchies all the time. Thankfully, with class syntax, it’s handled automatically so people forgetting is no longer an issue.

In theory, the instance may have an “own” constructor property, shadowing the one on the prototype. So if that’s a concern, you could go to the prototype:

console.log(Object.getPrototypeOf(c).constructor.isComponent);
class Component {
  static get isComponent() { return true; }

  constructor() {}
}

const c = new Component();
console.log(Object.getPrototypeOf(c).constructor.isComponent); // true

Alternatively, if you know what constructor it is, you can go direct to the source:

console.log(Component.isComponent);
class Component {
  static get isComponent() { return true; }

  constructor() {}
}

// const c = new Component(); <== Don't need it
console.log(Component.isComponent); // true

..but only if you know in advance that Component is the constructor you want.

For complete discussion, follow this link.