Hidden / Invisible Characters

Windows 98 had some tricks using ALT+some integer to add invisible characters. These are normally called  Control Characters.

The control characters U+0000–U+001F and U+007F come from ASCII. Additionally, U+0080–U+009F were used in conjunction with ISO 8859 character sets (among others). They are specified in ISO 6429 and often referred to as C0 and C1 control codes respectively. Most of these characters play no explicit role in Unicode text handling. The characters U+0000 , U+0009 (HT), U+000A (LF), U+000D (CR), and U+0085 (CR+LF) are commonly used in text processing as formatting characters.

This is how we can identify and remove them in a string;

string input; // this is your input string
string output = new string(input.Where(c => !char.IsControl(c)).ToArray());
Console.write(output.Trim());

For testing,

Excel can be used.

Click on the Cell where you want to add character. Click Insert -> Symbols;

Select “Basic Latin” in Subset and add empty space;

This will add a special character in selected cell before or after the value depending on the position.

Notepad++ is another alternative and can be used to add special characters in a string.

  1. Go to Edit > Character Panel to show the ASCII Insertion Panel.
  2. Put the cursor where you want to insert the character.
  3. Double-click the character (in the Character column) to insert.

For more info on NotePad++ special character handling, click here.

JavaScript: How to construct an array of json objects using map

What does map do ?

Answer: It creates a new array with the results of calling a function on every element in the calling array.

Example:

var numbers = [ 1, 2, 3, 4];
var multiplesOfTen = numbers.map( function(num) {
    return num * 10;
});
console.log(numbers); //prints [1, 2, 3, 4]
console.log(multiplesOfTen); //prints [10, 20, 30, 40]

How does JSON object look like?

Answer: JSON objects are written as key/ value pairs

Example:

var Person = { "name" : "Amy", "Age" : 15 }
console.log(Person.Age); //Prints 15

Let us solve a problem using map method. We have a JSON object say “orders” with lot of keys like name, description, date, status. We need an array of orders whose status is delivered. This array of orders will have information about order name and order description only.

Answer:

var orders = [ { "name" : "chain", "description" : "necklace chain", "status": "shipped"} , {"name": "pen", "description" : "ball pen", "status": "shipped"}, {"name": "book", "description" : "travel diary", "status": "delivered"},{"name": "brush", "description" : "paint brush", "status": "delivered"}];
console.log(orders); 
var orderInfo = orders.map( function(order) {
 if( order.status === "delivered"){
     var info = { "orderName": order.name,
                  "orderDesc": order.description
                 }
     return info;
 }
});
console.log(orderInfo);

Reference

https://www.w3schools.com/js/js_json_objects.asp

Method vs Linq based query syntax example

I need to make inner join on 3 tables; LedgerTypes, LedgerControl and Ledger.

Method based query example

//method based query
            
// your starting point - table in the "from" statement
var list = LedgerTypes
  //the source table of the inner join
  .Join(LedgerControl,
     //primary key (first part of sql "join" statement)
     t => t.Id,
     //foreign key (the second part of the "on" clause)
     lc => lc.ControllerTypeId, 
  (t, lc) => new { t, lc })   //new join
  // third table in the join clause
  .Join(Ledger, 
    //third table foreign key
    tc => tc.lc.Id, 
    //second table primary key
    l => l.ControllerID, 
  (tc, l) => new { tc, l })
      .Select(result => new {          //selection
       LedgerTypeId = result.tc.t.Id,
       LedgerTypeName = result.tc.t.ControllerTypeName,
       LedgerControlId = result.tc.lc.Id,
       LedgerControlName = result.tc.lc.ControllerCodeFullName,
       LedgerId = result.tc.lc.Id,
       LedgerName = result.tc.lc.ControllerCodeFullName
       // other assignments
});

Linq based query example

 //linq based query
var list = from t in LedgerTypes
    join lc in LedgerControl on t.Id equals lc.ControllerTypeId
    join l in Ledger on lc.Id equals l.ControllerID
    select new
       {
             LedgerTypeId = t.Id,
             LedgerTypeName = t.ControllerTypeName,
             LedgerControlId = lc.Id,
             LedgerControlName = lc.ControllerCodeFullName,
             LedgerId = l.Id,
             LedgerName = l.LedgerCodeFullName
            // other assignments
       };

I prefer query syntax because it’s readable and maintainable.

Resources

For more info read here and here

Delete a local git branch

How to delete a Test_Branch.

Switch to some other branch and delete Test_Branch, as follows:

$ git checkout master
$ git branch -d Test_Branch

If above command gives you error – The branch 'Test_Branch' is not fully merged. If you are sure you want to delete it and still you want to delete it, then you can force delete it using -D instead of -d, as:

$ git branch -D Test_Branch

To delete Test_Branch from remote as well, execute:

git push origin --delete Test_Branch

Check the link for more info.

Simplifying ADO.NET Code in .NET 6

When developers think of how to access data, many use the Entity Framework (EF), Dapper, NHibernate, or some other object-relational mapper (ORM). Each of these ORMs use ADO.NET to submit their SQL queries to the back-end database. So, why do many developers use ORMs instead of just using ADO.NET directly? Simply put, ORMs allow you to write. If each of these ORMs are simply wrappers around ADO.NET, can you write your own wrapper to cut down the amount of code you need to write? Absolutely! This series of articles shows you how to create a set of reusable wrapper classes to make it simpler to work with ADO.NET in .NET 6.

Read more on CodeMag web site here;

Simplifying ADO.NET Code in .NET 6: Part 1

Simplifying ADO.NET Code in .NET 6: Part II (Coming soon)